Answer:
C'(2,-1)
Step-by-step explanation:
1) Transform point C(1,2) to polar coordinates.
C(1,2)=C(x,y)=C(r,tetha)=C(squareroot(5),63.44Degrees)
2) Substract 90 degress to get C'
C'=(squareroot(5),-26.56)
3) Transform point C' to cartesian coordinates.
C'=(x,y)=(squarerott(5)cos(-26.56),squareroot(5)sin(-26.56)
=C'(2,-1)
Answer: (2,-1)
Step-by-step explanation:
The rule for rotation of a shape about 90° clockwise is given by :-
[tex](x,y)\rightarrow(y,-x)[/tex] [i.e. interchange x by y and y by negative of x ]
Given point : C (1, 2)
When point C is rotated 90° clockwise , then the ordered pair for its image C' will be :-
[tex]C(1,2)\rightarrow (2,-1)[/tex]
Hence, the ordered pair of C′ after point C (1, 2) is rotated 90° clockwise = (2,-1).
