Respuesta :
Answer:
Part 1) 11 is a rational number
Part 2) [tex]4\sqrt{3}[/tex] is a irrational number
Step-by-step explanation:
we know that
A Rational Number is a number that can be made by dividing two integers
Part 1) we have
[tex]\sqrt{121}[/tex]
we know that
[tex]121=11^{2}[/tex]
substitute
[tex]\sqrt{11^{2}}=(11^{2})^{\frac{1}{2}}=(11)^{\frac{2}{2}}=11[/tex]
Is a rational number, because i can express the number 11 as the ratio of two integers (as example 11/1)
Part 2) we have
[tex]\sqrt{48}[/tex]
we know that
[tex]48=2^{4}(3)[/tex]
substitute
[tex]\sqrt{2^{4}(3)}=(2^{4}(3))^{\frac{1}{2}}=4\sqrt{3}[/tex]
Is a irrational number, because cannot be expressed as the ratio of two integers
Answer:
The Simplified form of [tex]\sqrt{121}[/tex] is 11, which is a rational number.
The Simplified of [tex]\sqrt{48}[/tex] is [tex]4\sqrt{3}[/tex] which is an irrational number.
Step-by-step explanation:
Consider the provided root expression.
Irrational number: A number is irrational if it cannot be expressed by dividing two integers. The decimal expansion of Irrational numbers are neither terminate nor periodic.
Consider the expression [tex]\sqrt{121}[/tex]
The above expression can be written as:
[tex]\sqrt{11^{2}}=(11^{2})^{\frac{1}{2}}=(11)^{\frac{2}{2}}=11[/tex]
Hence, the Simplified of [tex]\sqrt{121}[/tex] is 11, which is a rational number.
Consider the expression [tex]\sqrt{48}[/tex]
The above expression can be written as:
[tex]\sqrt{48}=\sqrt{4^{2}\times3}=4\sqrt{3}[/tex]
Hence, the Simplified of [tex]\sqrt{48}[/tex] is [tex]4\sqrt{3}[/tex] which is an irrational number. Because the decimal expansion of the number is neither terminate nor periodic.