Answer:
1,076.09 milliliters of olive oil
Step-by-step explanation:
Remember that
Oil density is 0.92 g/mL
Gasoline density is 0.66 g/mL
1 L=1,000 mL
we know that
The density is equal to the ratio of the mass by the volume
Let
D -----> density in g/mL
m ----> the mass in grams
V ----> the volume in milliliters
[tex]D=\frac{m}{V}[/tex]
step 1
Find the mass of 1.50 L of gasoline
we have
[tex]V=1.50\ L[/tex]
Convert L to mL
[tex]V=1.50\ L=1.50(1,000)=1,500\ mL[/tex]
[tex]D=0.66\ g/mL[/tex]
substitute in the formula of density and solve for m
[tex]0.66=\frac{m}{1,500}[/tex]
[tex]m=0.66(1,500)=990\ g[/tex]
step 2
Find the volume of olive oil that have a mass of 990 grams
so
we have
[tex]m=990\ g[/tex]
[tex]D=0.92\ g/mL[/tex]
substitute in the formula of density and solve for the volume
[tex]0.92=\frac{990}{V}[/tex]
[tex]V=\frac{990}{0.92}=1,076.09\ mL[/tex]
therefore
1,076.09 milliliters of olive oil have the same mass as 1.50 L of gasoline
