Answer:
The value of house increased by $94,000.00.
The value of slope is [tex]\frac{94000}{11}[/tex]. It can be written as [tex]8545.\overline {45}[/tex].
Step-by-step explanation:
Given information:
The worth of house in 2019 = $250,000.00
The worth of house in 2008 = $156,000.00
Let y be the worth of house after x years. It means the two points are (2008,156000) and (2019, 250000).
The amount by which the value of house increases in 11 years is
[tex]Increase=$250,000.00-$156,000.00=$250,000.00-$94,000.00[/tex]
In 11 years, the value of house increased by $94,000.00.
The formula for slope is
[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
Two points are (2008,156000) and (2019, 250000). So, the slope is
[tex]slope=\frac{250000-156000}{2019-2008}[/tex]
[tex]slope=\frac{94000}{11}[/tex]
[tex]slope=8545.45454545[/tex]
[tex]slope=8545.\overline {45}[/tex]
Therefore the value of slope is [tex]\frac{94000}{11}[/tex]. It can be written as [tex]8545.\overline {45}[/tex].
