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(Thank you and please explain!) Here are two questions:
"The most common form of nylon (nylon-6) is 63.68% carbon, 12.38% nitrogen, 9.8% hydrogen, and 14.14% oxygen. Calculate the empirical formula for nylon-6."


"There are two binary compounds of mercury and oxygen. Heating either of them results in the decomposition of the compound, with oxygen gas escaping into the atmosphere while leaving a residue of pure mercury. Heating 0.6498 g of one of the compounds leaves a residue of 0.6018 g. Heating 4.172 g of the other compound results in a mass loss of 0.016 g. Determine the empirical formula of each compound."

THANK YOU FOR YOUR HELP!

Respuesta :

joseaaronlara

Answer:

The answer for the first problem is:  C₆N₁H₁₁O₁ or C₆NH₁₁O

Explanation:

Nylon composition:                     Mass        Divide by the atomic mass

Carbon                   63.68 %      63.68 g         63.68/ 12    = 5.3

Nitrogen                 12.38 %       12.38 g          12.38/14     = 0.88

Hydrogen                  9.8%           9.8 g           9.8/1           = 9.8

Oxygen                    14.14%         14.14 g          14.14/16      = 0.88

We choose the lowest number that is 0.88 for nitrogen and oxygen and divide the four results by this number

Carbon     5.3/0.88 = 6

Nitrogen    0.88/0.88 = 1

Hydrogen   9.8/0.88 = 11.1  = 11

Oxygen     0.88/ 0.88 = 1  

Then the empirical formula has this coefficients

        C₆N₁H₁₁O₁ or C₆NH₁₁O

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