please help me with this literal equation!

Answer:
x = [tex]\frac{n-20}{3a}[/tex]
Step-by-step explanation:
Given
[tex]\frac{3ax-n}{5}[/tex] = - 4
Multiply both sides by 5
3ax - n = - 20 ( add n to both sides )
3ax = - 20 + n = n - 20
Isolate x by dividing both sides by 3a
x = [tex]\frac{n-20}{3a}[/tex]
Answer:
x=(-20+n) / 3a
Step-by-step explanation:
(3ax-n) /5 = -4
⇒3ax-n = -20 [multiplied by 5 on both sides]
⇒3ax=-20+n [add "n" on both sides]
⇒x=(-20+n) / 3a [divide both sides by "3a"]