Answer:
m = 1.3 Kg
Explanation:
according to Specific Heat Formula :
Q = mc∆T
when Q is the heat energy in Joules
m is the mass of water
C is the specific heat its unit J/kg∙K
∆T change in temperature (the final t - the initial t)
by substitution:
Q = 190000 g * 4.184 J/g∘C *78
Q = 62006880 J
when The combustion of 1.0 lb of oil provides 2.2×107J
So lb of oil when Q = 62006880 J = 2.8 Ib
and when 1lb=454g
So 2.8 Ib = 1271.2 g = 1.3 Kg
