Answer:
The amount invested in the account that paid 8.2% is $4,000 and the amount invested in the account that paid 21.5% is $2,000
Step-by-step explanation:
Let
2x -----> the amount invested in the account that paid 8.2%
x -----> the amount invested in the account that paid 21.5%
in this problem we have
[tex]8.2\%=8.2/100=0.082\\21.5\%=21.5/100=0.215[/tex]
we know that
[tex]2x(0.082)+x(0.215)=758[/tex]
Solve for x
[tex]0.164x+0.215x=758[/tex]
[tex]0.379x=758[/tex]
[tex]x=\$2,000[/tex]
so
[tex]2x=\$4,000[/tex]
therefore
The amount invested in the account that paid 8.2% is $4,000 and the amount invested in the account that paid 21.5% is $2,000