Answer:
$6.25 or $6 and 25 cents
Step-by-step explanation:
Ms.Shanks collects [tex]\$1\dfrac{3}{4},\ \$\dfrac{3}{4},\ \$\dfrac{1}{4},\ \$2\dfrac{2}{4}[/tex],and [tex]\$1[/tex] from five of her students.
In total she collects
[tex]\$\left(1\dfrac{3}{4}+\dfrac{3}{4}+\dfrac{1}{4}+2\dfrac{2}{4}+1\right)=\$\left(1+2+1+\dfrac{3}{4}+\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{2}{4}\right)=\$\left(4+\dfrac{9}{4}\right)=\\ \\\$\left(4+2\dfrac{1}{4}\right)=\$6\dfrac{1}{4}[/tex]
Note that
[tex]\$6\dfrac{1}{4}=\$6.25[/tex] ($6 and 25 cents)
Now check in decimals:
[tex]\$1\dfrac{3}{4}=\$1.75\\ \\\$\dfrac{3}{4}=\$0.75\\ \\\$\dfrac{1}{4}=\$0.25\\ \\\$2\dfrac{2}{4}=\$2.50\\ \\\$1=\$1[/tex]
So, the sum is
[tex]\$1.75+\$0.75+\$0.25+\$2.50+\$1=\$1.75+\$1+\$3.50=\$1.75+\$4.50=\$6.25[/tex]
