Answer:
The answer to your question is: 8.01 x 10²⁵ atoms of helium
Explanation:
Data
Helium mass = 532 kg
Also from the periodic table:
He atomic mass = 4 gr
Avogrado's number: 6.023 x 10 ²³
Process (rule of three)
1 mol of helium ------------------- 4 kg
x moles of helium --------------- 532 kg
x = 532 x 1 / 4 = 133 moles of helium
1 mol of helium ----------------- 6.023 x 10²³ atoms
133 moles of helium ----------- x atoms of helium
atoms of helium = 133 x 6.023 x 10²³ / 1 = 8.01 x 10²⁵
