There are 110 adult tickets and 190 child tickets.
What is the process of solving for the given values from simultaneous equation ?
Let the number of adult tickets be x and the number of child tickets be y .
Given that a total of 300 tickets were sold and the receipts totaled $17,200.
∴ x + y = 300 .............. (1)
Also given tickets for a show are $70 for adults and $50 for children.
Therefore the total money collected is 70x + 50y.
∴ 70x + 50y = 17200 .............. (2)
Solving the simultaneous equations (1) and (2), we have
⇒ 70x + 50(300 - x) = 17200 [Substituting value of y from equation 1]
⇒ 70x - 50x + 15000 = 17200
⇒ 20x = 2200
∴ x = 110
Putting value of x in equation (1), we have -
⇒ y = 300 - 110 = 190
∴ y = 190
Thus there are 110 adult tickets and 190 child tickets.
To learn more about solving simultaneous equations, refer -
https://brainly.com/question/15165519
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