The first number is: 9
and the second number is: -15
Let the first number be : a
and the second number be: b
Now, we have:
Four times a number plus three times a second number is -9.
i.e. we have : 4a+3b= -9--------(1)
Also,
Twice the first number plus the second number is three.
i.e. 2a+b=3
i.e. we have: b=3-2a------(2)
Now, putting the value of b in equation (1) we have:
[tex]4a+3(3-2a)=-9\\\\4a+3\times 3-3\times 2a=-9\\\\4a+9-6a=-9\\\\4a-6a=-9-9\\\\-2a=-18\\\\2a=18\\\\a=\dfrac{18}{2}\\\\a=9[/tex]
and on putting the value of a in equation (2) we have:
[tex]b=3-2\times 9\\\\b=3-18\\\\b=-15[/tex]
