Answer:
1.3285 × 10⁻¹⁴ g of hydrazine
Explanation:
if 32 g of hydrizine (1 mole) contains 4 × 6.022 × 10²³ hydrogen atoms
then X g of hydrizine contains 1 × 10⁹ hydrogen atoms
X = (32 × 1 × 10⁹) / (4 × 6.022 × 10²³)
X = 1.3285 × 10⁻¹⁴ g of hydrazine
Answer: The mass of hydrazine having 1 billion hydrogen atoms is [tex]1.328\times 10^{-14}g[/tex]
Explanation:
Molar mass of hydrazine = 32 g/mol
We are given:
A chemical compound having formula [tex]N_2H_4[/tex]
1 mole of hydrazine contains 2 moles of nitrogen atoms and 4 moles of hydrogen atoms
Number of hydrogen atoms = [tex]1.000\times 10^9[/tex]
According to mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules.
So, 1 mole of hydrazine will contain = [tex]4\times 1\times 6.022\times 10^{23}=2.4088\times 10^{24}[/tex] number of hydrogen atoms.
Thus, mass of [tex]2.4088\times 10^{24}[/tex] number of hydrogen atoms present in hydrazine is 32 grams
So, mass of [tex]1.000\times 10^9[/tex] number of hydrogen atoms present in hydrazine will be = [tex]\frac{32g}{2.4088\times 10^{24}}\times 1.000\times 10^9=1.328\times 10^{-14}g[/tex]
Hence, the mass of hydrazine having 1 billion hydrogen atoms is [tex]1.328\times 10^{-14}g[/tex]
