kellyalvarado00m
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Jotham needs 70 liters of a 50% alcohol solution. He has a 30% solution and an 80% solution available. How many liters of
the 30% solution and how many liters of the 80% solution should he mix to make the 50% solution?

Respuesta :

x+y=70. (30x+80y)/(100x+100y)=50/100

Answer:

42 liters of 30% alcohol solution will be needed.

28 liters of 80% solution will be needed.

Step-by-step explanation:

Jotham needs 70 liters of a 50% alcohol solution.

Let the 30% solution needed be x.

We get the following equation:

[tex]70\times0.5=0.30x+0.80(70-x)[/tex]

Solving this we get;

[tex]35=0.30x+56-0.80x[/tex]

=> [tex]35=56-0.50x[/tex]

=> [tex]0.50x=56-35[/tex]

=> [tex]0.50x=21[/tex]

x = 42

Hence, 42 liters of 30% alcohol solution will be needed.

And [tex]70-42=28[/tex] liters of 80% solution will be needed.

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