Answer:
The amount invested in certificate of deposit paying at 8% was $6,000 and the amount invested in a savings account at 9% was $3,000
Step-by-step explanation:
The question in English is
Vanessa wants to invest $9,000. She invests part in certificate of deposit paying at 8% and the rest in a savings account at 9% per year. If the interest earned in one year was $750, How much did you invest in each one?
Let
x -----> the amount invested in certificate of deposit paying at 8%
(9,000-x) -----> the amount invested in a savings account at 9% per year
Remember that
[tex]8\%=8/100=0.08[/tex]
[tex]9\%=9/100=0.09[/tex]
we know that
[tex]750=0.08(x)+0.09(9.000-x)[/tex]
Solve for x
[tex]750=0.08x+810-0.09x[/tex]
[tex]0.09x-0.08x=810-750[/tex]
[tex]0.01x=60[/tex]
[tex]x=\$6,000[/tex]
[tex]9,000-x=\$3,000[/tex]
therefore
The amount invested in certificate of deposit paying at 8% was $6,000 and the amount invested in a savings account at 9% was $3,000
