Answer:
[tex]\boxed{p=220kg.\frac{m}{s}}[/tex]
Explanation:
Newton’s second law says that the net force [tex]\Sigma \vec{F}[/tex] acting on a particle equals the time rate of change of the product of the particle’s mass and velocity. This product is called the momentum, or linear momentum. In this problem we know that:
[tex]m=100.0kg \\ \\ v=2.20m/s \\ \\ r=30.3m[/tex]
So the momentum is:
[tex]p=mv \\ \\ p=(100.0)(2.20) \\ \\ \boxed{p=220kg.\frac{m}{s}}[/tex]
