Explanation:
An apple falls from a tree and hits the ground 11.9 m below. We need to find the speed with which it hits the ground. It can be calculated using the conservation of energy as :
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 11.9}[/tex]
v = 15.2 m/s
So, the speed with which it hits the ground is 15.2 m/s. Hence, this is the required solution.
