Respuesta :
Answer:
minimum distance will be 13.33 m
Explanation:
We have given the speed of both the car = 80 km/h
We know that 1 km =1000 m
And 1 hour = 60×60 =3600 sec
So [tex]80km/h=\frac{80\times 1000}{3600}=22.22m/sec[/tex]
Reaction time is given as t = 0.60 sec
Minimum distance will be equal to the distance driver needed during reaction time
So minimum distance = u ×t =22.22 ×0.60=13.33 m
The minimum distance behind the car in front to drive so that the crash into the car's rear end if the driver of car 1 slams on the brakes should be 13.33 m.
What is speed of a object?
Speed or velocity of a object is the ratio of distance traveled by the object with the time taken.
Given information-
The speed of car 1 and car 2 is 80 km/h.
The reaction time of the car 2 driver is 0.60 seconds.
Convert the unit of speed into the m/s by multiplying it with 5/18 as,
[tex]v=\dfrac{80\times5}{18} \\v=22.22 \rm m/s[/tex]
Thus the speed of the car is 22.22 m/s.
Now the reaction time is 0.60 seconds. Thus the minimum distance can be given as,
[tex]d=22.22\times0.6\\d=13.33 m[/tex]
Hence the minimum distance behind the car in front to drive so that the crash into the car's rear end if the driver of car 1 slams on the brakes should be 13.33 m.
Learn more about the velocity here;
https://brainly.com/question/6504879
