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Valeria is ordering medals for her school's track meet. Company A charges $4.50 for each medal and a one-time engraving fee of $40. Company B charges $6.50 for each medal and a one-time engraving fee of $20. Which inequality can be used to find x, the least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B? A) 4.5 + 40x < 6.5 + 20x B) 4.5 + 40x > 6.5 + 20x C) 4.5x + 40 < 6.5x + 20 D) 4.5x + 40 > 6.5x + 20

Respuesta :

gxvindoesnotcare

Answer:

The answer is C) 4.5x + 40 < 6.5x + 20

Step-by-step explanation:

isyllus

Answer:

4.5x + 40 < 6.5x + 20

C is correct

Step-by-step explanation:

Valeria is ordering medals for her school's track meet.

Let total charge be $y and number of medals be x

#Company A charges $4.50 for each medal and a one-time engraving fee of $40.

  • For company A total charge, y = variable + one time fee

 y = 4.5x + 40

#Company B charges $6.50 for each medal and a one-time engraving fee of $20.

  • For company B total charge, y = variable + one time fee

 y = 6.5x + 20

The least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B

Company A < Company B

   4.5x + 40 < 6.5x + 20

              2x > 20

                x > 10

Hence, The least value of x is 10 and inequality "  4.5x + 40 < 6.5x + 20 "

             

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