One of the buffers that contribute to pH stability in human blood is carbonic acid (H2CO3). Carbonic acid is a weak acid that, when placed in an aqueous solution, dissociates into a bicarbonate ion (HCO3-) and a hydrogen ion (H ), as noted below. If the pH of blood drops, one would expect _____. One of the buffers that contribute to pH stability in human blood is carbonic acid (H2CO3). Carbonic acid is a weak acid that, when placed in an aqueous solution, dissociates into a bicarbonate ion (HCO3-) and a hydrogen ion (H ), as noted below. If the pH of blood drops, one would expect _____. the HCO3- to act as a base and remove excess H by the formation of H2CO3 the concentration of bicarbonate ions (HCO3-) to increase the HCO3- to act as an acid and remove excess H by the formation of H2CO3 a decrease in the concentration of H2CO3 and an increase in the concentration of HCO3-

Respuesta :

Answer: the HCO3- to act as a base and remove excess H by the formation of H2CO3

Explanation:

H2CO3 in an aqueous solution is a buffer. This means the reaction is the following:

H2CO3 ------ HCO3- + H+

Then, the HCO3- that was formed acts as a base (absorbing a proton) like this

HCO3- + H+ ------- H2CO3

If there was an increase in H+, there would be an increase in the second reaction in an effort to neutralize that acid, thus making the H2CO3 more concentrated

The pH is used to check the degree of acidity or the alkalinity of a solution.

The pH of the human blood is neutral and buffer helps in maintaining its stability.

Here, Carbonic acid acts as a buffer, and its dissociation is given as follows:

[tex]\mathbf{\matbf{H_2CO_3 \leftrightarrow HCO^{-}_3 + H^+ }}[/tex]

The removal of excess H⁺ ions by HCO₃⁻ prevents the blood from becoming acidic. Hence, if the blood drops, the pH of the blood decreases, and one will expect that HCO₃⁻ will function as a base, removing excess H⁺ and forming H₂CO₃.

Therefore, we can conclude that, if the pH of blood drops, one would expect the HCO₃⁻ to act as a base and remove the excess H⁺ with the formation of H₂CO₃.

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