Respuesta :
Answer:
velocity [tex]v=6.037\times 10^6m/sec[/tex]
Explanation:
We have given mass of electron [tex]m=9.11\times 10^{-31}kg[/tex]
De broglie wavelength is given as [tex]\lambda =1.2\times 10^{-10}m[/tex]
According to de broglie hypothesis [tex]\lambda =\frac{h}{mv}[/tex], here h is plank's constant , m is mass of electron and v is velocity of electron
Value of plank's constant [tex]h=6.6\times 10^{-34}[/tex]
Putting all these value in wavelength formula
[tex]1.2\times 10^{-10}=\frac{6.6\times 10^{-34}}{9.11\times 10^{-31}\times v}[/tex]
[tex]v=6.037\times 10^6m/sec[/tex]
The wavelength is also described as the distance between two places in a wave that has the exact oscillation phase. The velocity of an electron that has a de Broglie wavelength will be 6.037×10⁶ m/sec.
What is wavelength?
The wavelength is also defined as the length between two places in a wave that has the exact oscillation phase.
The heigh of a wave is calculated in its propagation path. The wavelength is calculated in meters, centimeters, nanometres, and other units since it is a distance measurement.
m is the mass of the electron =9.11×10⁻³¹ kg
λ is de Broglie wavelength = 1.2×10⁻¹⁰ m
h is plank's constant=6.6×10⁻³⁴
Relation of de broglie wavelength
[tex]\rm \lambda= \frac{h}{mv} \\\\\rm v= \frac{h}{m\lambda}\\\\\rm v= \frac{6.6\times10^{-34}}{9.11\times10^{-31}\times1.2\times10^{-10}}[/tex]
Hence the velocity of an electron that has a de Broglie wavelength will be 6.037×10⁶ m/sec.
To learn more about the wavelength refer to the link;
brainly.com/question/7143261
