The initial velocity of the bird before the gust of wind : 4 m/s
An equation of uniformly accelerated motion
[tex]\large {\boxed {\bold {x = xo + vo.t + \frac {1} {2} at ^ 2}}}[/tex]
v = vo + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo/vi = initial speed
vt/vf = speed on t /final speed
a = acceleration
Acceleration is a change in speed within a certain time interval
a = Δv /Δ t
[tex]\displaystyle a=\frac{v2-v1}{t2-t1}[/tex]
Let complete the task :
A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5 m/s² for 3 s. After the wind stops, the bird is flying to the right with a velocity of 2.5 m/s.
Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?
we can use formula :
vf = vi + a.t
vf = final velocity = 2.5 m/s
vi = asked
a = - 0.5 m/s²(leftward=negative)
t = 3 s
then :
[tex]\displaystyle 2.5=vi-0.5.3\\\\vi=2.5+1.5\\\\vi=\boxed{\bold{4\frac{m}{s}}}[/tex]
The car reach the end of the road
https://brainly.com/question/13750982
Keywords: uniformly accelerated motion, distance, velocity, acceleration
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