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Answer:
As you can easily see in the image attached, with a dispersive replication you obtain two DNA molecules with equally dispersed fragments of 14 and 15N, thus, obtaining and intermediate band in the gradient, between the 14 and 15N bands.
The same would occur for the semiconservative model, as after one round of replication you obtain 2 DNA molecules, each containing one 14N strand and a 15N strand. Thus, the mass, therefore the density, of each molecule would be an intermidiate between a fully 14N and a fully 15N DNA molecule.
Finally, if the replication occurs following a conservative model, after one round of replication, you would get a DNA molecule containing only 14N and another containing only 15N, thus, obtaining two distinct bands, each one corresponding to the density of its corresponding nitrogen isotope.
Studying the patterns after only one round of replication lets you discard the conservative model, but you couldn't be able to discern between the dispersive and semiconservative ones. For this, you would need to analyze the patterns after a second round of replication

The semiconservative model is the correct model for the replication of DNA.
What is the correct model of replication?
Meselson and Stahl designed an experiment to determine the correct model of replication. They predicted the following patterns,
- Conservative model: in which the newly formed dsDNA strands have complete only N-14 in their nitrogenous base.
- Semiconservative model: in which the one strand of newly formed dsDNA has N-15 while the other has N-14.
- Dispersive model: in which both the strands of newly formed dsDNA have mixed N-14 and N-15.
After the first round of replication, they found that one strand of newly formed dsDNA has N-15 while the other has N-14.
Therefore, the semiconservative model is the correct model for the replication of DNA.
Learn more about the semiconservative model:
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