Respuesta :
Answer:
17.1195 grams of nitric acid are produced.
Explanation:
[tex]3NO_2+H_2O\rightarrow 2HNO_3+NO[/tex]
Moles of nitrogen dioxide :
[tex]\frac{25.0 g}{56 g/mol}=0.5434 mol[/tex]
According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.
Then 0.5434 moles of nitrogen dioxides will give:
[tex]\frac{2}{3}\times 0.5434 mol=0.3623 mol[/tex] of nitric acid.
Mass of 0.3623 moles of nitric acid :
[tex]0.3623 mol\times 63 g/mol=22.8260 g[/tex]
Theoretical yield = 22.8260 g
Experimental yield = ?
[tex]\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100[/tex]
[tex]75\%=\frac{\text{Experimental yield}}{22.8260 g}[/tex]
Experimental yield of nitric acid = 17.1195 g
