A 24% acid solution is mixed with a 14% acid solution to form a 19% acid solution. How many liters of the 24% acid solution are used to make 10 liters of the 19% acid solution?

Respuesta :

Answer: 5 Liters

Explanation:

According to the dilution law,

[tex]M_1V_1+M_2V_2=M_3V_3[/tex]

where,

[tex]M_1[/tex] = concentration of first solution = 24%

[tex]V_1[/tex] = volume of first solution = x L

[tex]M_2[/tex] = concentration of second solution = 14%

[tex]V_2[/tex] = volume of second solution = (10-x) L

[tex]M_3[/tex] = concentration of final solution = 19%

[tex]V_2[/tex] = volume of final solution = 10 L

Putting i the values, we get:

[tex]24\times x+14\times (10-x)=19\times 10[/tex]

[tex]x=5L[/tex]

Therefore, 5 Liters of the 24% acid solution are used to make 10 liters of the 19% acid solution.