In the theory of relativity, the mass of a particle with velocity v is [tex]m = \frac{m_0}{\sqrt{1 - v^2/c^2}}[/tex], where m₀ is the mass of the particle at rest and c is the speed of light. What happens as v → c⁻?
A. m → m₀
B. m → 1
C. m → 0
D. m → m⁻

Respuesta :

Answer:

The mass [tex]m[/tex] would tend to infinite.

v→c ⇒ m→∞

Explanation:

We can calculate the following limit easily:

[tex]\lim_{v \to c} \sqrt{1-\frac{v^{2} }{c^{2} } }=\sqrt{1-1} =0\\[/tex]

So,

[tex]\lim_{v \to c} \frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} }} }=infinite[/tex].

This means that mass will only increase as velocity approaches light velocity [tex]c[/tex]. It also means that a particle would need infinite energy to travel at light speed.