The period T of a simple pendulum is the amount of time required for it to undergo one complete oscillation. If the length of the pendulum is L and the acceleration of gravity is g, then T is given by [tex]T = 2\pi L^pg^q[/tex]
Find the powers p,q required for dimensional consistency.

Respuesta :

Answer:

1/2, - 1/2

Explanation:

[tex]T=2\pi L^{p}\times g^{q}[/tex]

Write the dimensions on both the sides

The dimensions of T are [T]

The dimensions of L are [L]

The dimensions of g are [tex][LT^{-2}][/tex]

So, [tex][T]=[L]^{p}][LT^{-2}]^{q}[/tex]

[tex][T]=[L^{p+q}T^{-2q}][/tex]

Now compare the dimensions on both the sides for the corresponding terms

p + q  = 0 ...... (1)

-2q = 1    ......... (2)

By solving equation (1) and (2), we get

q = - 1/2

p = 1 / 2

Thus, the value of p  and q are 1/2 and - 1/2 respectively.