Respuesta :
Answer:
The absorbance at 500 nm is [tex]A_2 = 0.52A[/tex]
Explanation:
BY USING proportionality relationshiop between concentration and absorbance , which is given as
[tex]\frac{c_1}{c_2} =\frac{A_1}{A_2}[/tex]
FROM THE DATA WE HAVE
[tex]c_1 = 0.10 M[/tex]
[tex]A_1 = .26A[/tex]
[tex]c_2 = 0.20 M[/tex]
so, from above relation we have
[tex]A_2 = \frac{c_2 A_1}{c_1}[/tex]
[tex]A_2 = \frac{0.20*0.26}{0.10}[/tex]
[tex]A_2 = 0.52A[/tex]
Answer : The measured absorbance of 0.20 M solution is 0.52
Explanation :
Using the proportionality relationship between concentration and absorbance, we use:
[tex]\frac{C_1}{C_2}=\frac{A_1}{A_2}[/tex]
where,
[tex]C_1[/tex] = concentration of solution 1 = 0.10 M
[tex]C_2[/tex] = concentration of solution 2 = 0.20 M
[tex]A_1[/tex] = absorbance of solution 1 = 0.26
[tex]A_2[/tex] = absorbance of solution 2 = ?
Now put all the given values in the above expression, we get:
[tex]\frac{0.10M}{0.20M}=\frac{0.26}{A_2}[/tex]
[tex]A_2=0.52[/tex]
Therefore, the measured absorbance of 0.20 M solution is 0.52
