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The reaction: (CH3)3CBr + OH− → (CH3)3COH + Br− in a certain solvent is first order with respect to OH−. In several experiments, the rate constant k was determined at different temperatures. A plot of ln(k) vs 1/T was constructed and the slope of the line was -1.10 x 104 K with a y-intercept of 33.5. What is the value for k at a temperature of 25°C? A. 3.69 × 10-7 s-1 B. 3.51 s-1 C. 3.23 × 10-2 s-1 D. 1.10 × 104 s-1

Respuesta :

dvelasquez90

Answer:

C

Explanation:

This is the Arrehnius equation in lineal form, lnK = -Ea/RT + lnA.

so the slope corresponds to -Ea/R and the intercept is lnA. So from the slope we can calculate the Ea Ea=-(-1.10*10^4)*8.314=9.1*10^4 J/lol

A=e^(33.5)=3.53*10^14

Finally with these values and using the Arrehnius equation we can calculate K at 25°C.

k=Ae^-(Ea/RT)

k=(91.06)e^-(9.1*10^4/(8.314*298))

k=3.23*10^-2

The study of chemicals and bonds is called chemistry.

The correct answer to the question is C

What is the Arrhenius equation?

  • The Arrhenius equation is a formula for the temperature dependence of reaction rates

According to the question,

This is the Arrhenius equation in lineal form, [tex]lnK = \frac{-Ea}{RT} + lnA.[/tex]

so the slope corresponds to -Ea/R and the intercept is lnA. So from the slope,

we can calculate the Ea

[tex]Ea=-(-1.10*10^4)*8.314=9.1*10^4 J/lol[/tex]

[tex]A=e^{(33.5)}\\=3.53*10^14[/tex]

Finally with these values and using the Arrhenius equation we can calculate K at 25°C.

k=[tex]Ae^\frac{-Ea}{RT}[/tex]

k=[tex](91.06)e^\frac{-(9.1*10^4}{(8.314*298))}[/tex]

k=[tex]3.23*10^{-2[/tex]

Hence, the correct answer is mentioned above.

For more information about the equation, refer to the link:-

https://brainly.com/question/14688752

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