Respuesta :
The slope of the line formed from ln(k) vs 1/T represents [tex]-\left(\frac{E_{a}}{R}\right)[/tex]
Answer: Option D
Explanation:
Based on the Arrhenius equation, we can calculate the activation energies if rate constant is well-known, or vice versa. It also expresses mathematically the relationship: as the activation energy component [tex]E_{a}[/tex] increases, the rate constant k decreases, so the reaction rate decreases.
The Arrhenius equation is [tex]k=A e^{-E a / R T}[/tex]
Taking logarithm on both the sides we will have [tex]\ln k=-\frac{E_{a}}{R T}+\ln A[/tex]
We know the equation y=mx+c where ‘ m ‘ is the slope and c is the Intercept
Equating y=mx+c to the logarithmic equation
we have y= ln k
[tex]m=-\frac{E_{a}}{R}[/tex]
x=1/T and
c =ln A
so, slope [tex]m=\frac{-E_{a}}{R}[/tex] that is the answer
