The sum of two numbers is 98. Their difference is 22. Write a system of equations that describes this situation. Solve by elimination to find the two numbers.
a.
x + y = 98
x – y = 22
55 and 33
c.
x – y = 98
x + y = 22
59 and 39
b.
x + y = 98
x – y = 22
60 and 38
d.
x + y = 22
y – x = 98
55 and 39

Respuesta :

Answer:

x + y = 98

x - y = 22

2x = 120

x = 60

x + 60 = 98

x = 38

the answer is b

The correct ans to this question is Option  (C). The Value of X comes out to be 60 and y comes out to be 38.


What is elimination Method?

In elimination method we are required to add or subtract the given equations in order to get equation in one variable form. Then after calculating that variable's value we'll be putting in the original equation to get the values of second variable.

When the coefficients of one of the variable are same we subtract the equations in order to eliminate the variable whereas if the coefficients are opposite then we need to add the equations to eliminate the variable.

Example:

3x+2y=5

2x-2y=0

As we can see the coefficients of variable y is opposite so we need to add the equations.

On addition we get

5x=5

⇒x=1

we'll put this value in one of the equations to get the value of y

2(1)-2y=0

2-2y=0

⇒2=2y

y=1

Given in the question,

Lets say X and Y are the two numbers

so,

X+Y=98

X-Y=22

On addition we get,

2X=120

X=60

Putting this value in the equation

60+Y=98

Y=98-60

Y=38

To learn more about elimination method,check this

https://brainly.in/question/3955838

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