Respuesta :
Answer:
[tex]V_{avg}=54.90\ km/h[/tex]
Explanation:
Given that
Drive 113 km at 47 km/h and another 113 km at 66 km/h.
When distance is same then average velocity can be found by using below formula:
[tex]V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}[/tex]
Here
[tex]V_1= 47\ km/h[/tex]
[tex]V_2= 66\ km/h[/tex]
Now by putting the values
[tex]V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}[/tex]
[tex]V_{avg}=\dfrac{2\times 47\times 66}{47+66}[/tex]
So
[tex]V_{avg}=54.90\ km/h[/tex]
Answer:
Average velocity v = 54.90 km/h
Explanation:
We have given the distance d = 113 km
First speed = 47 km/h
Time taken to cover 113 km with speed of 47 km/h
[tex]t=\frac{distance}{speed}=\frac{113}{47}=2.4042h[/tex]
Time taken to cover 113 km with speed of 66 km/h
[tex]t=\frac{distance}{speed}=\frac{113}{66}=1.7121h[/tex]
So total time = 2.4042+1.7121 =4.1163 hour
Total distance = 113+113=226 km
So average velocity [tex]v=\frac{distance}{time}=\frac{226}{4.1163}=54.90km/h[/tex]