Respuesta :
Answer : The mass of water produced will be 32.78 grams.
Explanation : Given,
Mass of [tex]C_5H_{12}[/tex] = 21.9 g
Molar mass of [tex]C_5H_{12}[/tex] = 72.15 g/mole
Molar mass of [tex]H_2O[/tex] = 18 g/mole
First we have to calculate the moles of [tex]C_5H_{12}[/tex].
[tex]\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles[/tex]
Now we have to calculate the moles of [tex]H_2O[/tex].
The balanced chemical reaction will be,
[tex]C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)[/tex]
From the balanced reaction we conclude that
As, 1 mole of [tex]C_5H_{12}[/tex] react to give 6 moles of [tex]H_2O[/tex]
So, 0.3035 moles of [tex]C_5H_{12}[/tex] react to give [tex]0.3035\times 6=1.821[/tex] moles of [tex]H_2O[/tex]
Now we have to calculate the mass of [tex]H_2O[/tex].
[tex]\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O[/tex]
[tex]\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g[/tex]
Therefore, the mass of water produced will be 32.78 grams.
