contestada

For the following example, identify the following:

F2(l) → F2(g)

A. at low temperature, the reaction is spontaneous and ΔG < 0 and at high temperature, the reaction is spontaneous and ΔG < 0
B. at low temperature, the reaction is nonspontaneous and ΔG > 0 and at high temperature, the reaction is spontaneous and ΔG < 0
C. at low temperature, the reaction is spontaneous and ΔG < 0 and at high temperature, the reaction is nonspontaneous and ΔG > 0
at low temperature, the reaction is nonspontaneous and ΔG > 0 and at D. high temperature, the reaction is nonspontaneous and ΔG > 0
It is not possible to determine without more information.

Respuesta :

Answer: Option (A) is the correct answer.

Explanation:

According to the Gibb's free energy conditions:

     If [tex]\Delta G[/tex] < 0, then reaction is spontaneous.

     If [tex]\Delta G[/tex] > 0, then reaction is non-spontaneous.

      If [tex]\Delta G[/tex] = 0, then reaction is equilibrium.

Since, the given reaction is [tex]F_{2}(l) \rightarrow F_{2}(g)[/tex]. It denotes that liquid state of fluorine is changing into gaseous state. And, the boiling point of fluorine is very low.

Therefore, at low and high temperature fluorine is a gas. Hence, the reaction is spontaneous in nature.

Thus, we can conclude that the statement at low temperature, the reaction is spontaneous and [tex]\Delta G[/tex] < 0 and at high temperature, the reaction is spontaneous and [tex]\Delta G[/tex] < 0, is correct.