Respuesta :
Answer:
1,520.00 calories
Explanation:
Water molecules are linked by hydrogen bonds that require a lot of heat (energy) to break, which is released when the temperature drops. That energy is called specific heat or thermal capacity (ĉ) when it is enough to change the temperature of 1g of the substance (in this case water) by 1°C. Water ĉ equals 1 cal/(g.°C).
Given that ĉ = Q / (m.ΔT),
where Q= calories transferred between the system and its environment or another system (unity: calorie or cal) (what we are trying to find out),
m= mass of the substance (unity: grams or g), and
ΔT= difference of temperature (unity: Celsius degrees or °C); and
m= 95g and ΔT= 16°C:
Q= 1 cal/(g.°C).95g.16°C = 1,520.00 cal
Taking into account the definition of calorimetry, when 95 g of water cools from 45 ∘C to 29 ∘C, the calories lost are 1520.
Calorimetry
In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .).
The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
- Q is the heat exchanged by a body of mass m.
- c: specific heat substance.
- ΔT is the temperature variation.
Calories lost
In this case, you know that:
- Q= ?
- c= 1 [tex]\frac{cal}{gC}[/tex]
- m= 95 g
- ΔT= 29 C - 45 C= -16 C
Replacing in the expression to calculate heat exchanges:
Q= 1 [tex]\frac{cal}{gC}[/tex]× 95 g× (-16 C)
Solving:
Q= -1520 cal
In summary, when 95 g of water cools from 45 ∘C to 29 ∘C, the calories lost are 1520.
Learn more about calorimetry:
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