Answer:Average speed is greater than average velocity.
Explanation :
Given
student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position
Let x be the length of track and the whole process takes t time
For average speed [tex]=\frac{distance\ traveled}{time\ taken}[/tex]
Average speed[tex]=\frac{2x}{t}[/tex]
For average velocity [tex]=\frac{Displacement}{time\ taken}[/tex]
Since displacement is zero as she returns to its initial position.
Average velocity=0
Therefore Average speed is greater than average velocity.