Explanation:
Given that,
Electrostatic force, [tex]F=3.7\times 10^{-9}\ N[/tex]
Distance, [tex]r=5\ A=5\times 10^{-10}\ m[/tex]
(a) [tex]F=\dfrac{kq^2}{r^2}[/tex], q is the charge on the ion
[tex]q=\sqrt{\dfrac{Fr^2}{k}}[/tex]
[tex]q=\sqrt{\dfrac{3.7\times 10^{-9}\times (5\times 10^{-10})^2}{9\times 10^9}}[/tex]
[tex]q=3.2\times 10^{-19}\ C[/tex]
(b) Let n is the number of electrons are missing from each ion. It can be calculated as :
[tex]n=\dfrac{q}{e}[/tex]
[tex]n=\dfrac{3.2\times 10^{-19}}{1.6\times 10^{-19}}[/tex]
n = 2
Hence, this is the required solution.
