Answer: 2.54 s
Explanation:
If we are talking about a constant acceleration, we can use the following equation:
[tex]V_{f}=V_{o}+2at[/tex]
Where:
[tex]V_{f}=28 m/s[/tex] is the final velocity of the car
[tex]V_{o}=0t[/tex] is the finitial velocity of the car (it started from rest)
[tex]a=5.5 m/s^{2}[/tex] is the constant acceleration of the car
[tex]t[/tex] is the time it takes to reach [tex]V_{f}[/tex] with the given constant velocity
Hence:
[tex]V_{f}=2at[/tex]
Clearing [tex]t[/tex]:
[tex]t=\frac{V_{f}}{2a}[/tex]
[tex]t=\frac{28 m/s}{2a(5.5 m/s^{2})}[/tex]
Finally:
[tex]t=2.54 s[/tex]
