Answer:
0.375 grams are needed to make 25 mL solution.
Explanation:
Mass of [tex]AgNO_3[/tex] cuprous nitrate required to make 1 l of solution = 15 g.
1 L = 1000 mL
Mass of [tex]AgNO_3[/tex] cuprous nitrate required to make 1000 mL of solution = 15 g
Mass of [tex]AgNO_3[/tex] cuprous nitrate required to make 1 mL of solution:
[tex]=\frac{15}{1000} g[/tex]
Mass of [tex]AgNO_3[/tex] cuprous nitrate required to make 25 mL of solution:
[tex]=\frac{15}{1000} \times 25 g=0.375 g[/tex]
0.375 grams are needed to make 25 mL solution.