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In the previous question, the person had an initial velocity of 8m/s and a constant acceleration of −4m/s2. How would the maximum distance he travels to the right of the origin change if instead his initial velocity were doubled (vx,0=16m/s)?

Respuesta :

jorgezarate

Answer:

Distance maximum

Xmax = 32m

Explanation:

Kinematics equation between velocities and distance:

[tex]Vf^{2} =Vo^{2} +2ax[/tex]

For the distance maximum the final velocity is zero:

[tex]x = Xmax[/tex] ⇒ [tex]Vf=0[/tex]

then, the equation becomes:

[tex]Xmax= - \frac{Vo^{2}}{2a}[/tex]

We replace the values for the initial velocity and acceleration

Vo=16m/s; a = -4m/s2

Finally:

[tex]Xmax=16^{2} /8=32m[/tex]

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