Respuesta :
[tex]\bf y= \stackrel{\stackrel{m}{\downarrow }}{\cfrac{4}{5}}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
Answer:
The slope of the given line is:
[tex]\dfrac{4}{5}[/tex]
Step-by-step explanation:
We know that if a line is represented in the slope intercept form i.e.
[tex]y=mx+c[/tex]
then m represents the slope of the line and c represents the y-intercept of the line.
Here we are given a equation of a line as follows:
[tex]y=\dfrac{4}{5}x-3[/tex]
i.e. on comparing the equation with the slope-intercept form of the line we have the slope of the line is:
[tex]m=\dfrac{4}{5}[/tex]
