Answer: The freezing point of a 0.765 m solution of nitrobenzene in naphthalene is [tex]74.6^0C[/tex]
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=(80.3-T_f)^0C[/tex] = Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte such as nitrobenzene)
[tex]K_f[/tex] = freezing point constant = [tex]7.45^0C/m[/tex]
m= molality = 0.765
[tex](80.3-T_f)^0C=1\times 7.45\times 0.765[/tex]
[tex]T_f=74.6^0C[/tex]
Thus the freezing point of a 0.765 m solution of nitrobenzene in naphthalene is [tex]74.6^0C[/tex]