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25.0 g of mercury is heated from 25°C to 155°C, and absorbs 455 joules of heat
in the process. Calculate the specific heat capacity of mercury.

Respuesta :

joseaaronlara

Answer:

The answer to your question is: Cp = 0.14 J/g°C

Explanation:

Data

mass = 25 g

T1 = 25°C

T2 = 155°C

Q = 455 joules

Cp = ?

Formula

Q = mCpΔT

Clear Cp from the equation    Cp = Q /(mΔT)

Cp = 455 /((25(155-25))

Cp = 455 / (25(130))

Cp = 455 / 3250

Cp = 0.14 J/g°C

Eduard22sly

The specific heat capacity of the mercury is 0.14 J/gºC

To solve this question, we'll begin by calculating the change in the temperature of the mercury. This is illustrated below:

Initial temperature of water (T₁) = 25 °C

Final temperature of water (T₂) = 155 °C

Change in temperature of water (ΔT) =?

ΔT = T₂ – T₁

ΔT = 155 – 25

Change in temperature of mercury (ΔT) = 130 °C

  • Finally, we shall determine the specific heat capacity of the mercury. This can be obtained as follow:

Mass of mercury (M) = 25 g

Change in temperature of mercury (ΔT) = 130 °C

Heat absorbed (Q) = 455 J

Specific heat capacity of mercury (C) =?

Q = MCΔT

455 = 25 × C × 130

455 = 3250 × C

Divide both side by 3250

[tex]C = \frac{455}{3250} \\\\[/tex]

C = 0.14 J/gºC

Therefore, the specific heat capacity of the mercury is 0.14 J/gºC

Learn more: https://brainly.com/question/24813298

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