Respuesta :
same as before here, the bird is up above and from there goes down, so we sum up both amounts.
[tex]\bf \stackrel{mixed}{528\frac{1}{5}}\implies \cfrac{528\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{2641}{5}}~\hfill \stackrel{mixed}{89\frac{3}{5}}\implies \cfrac{89\cdot 5+3}{5}\implies \stackrel{improper}{\cfrac{448}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{2641}{5}+\cfrac{448}{5}\implies \stackrel{\textit{using an LCD of 5}}{\cfrac{(1)2641+(1)448}{5}}\implies \cfrac{3089}{5}\implies 617\frac{4}{5}[/tex]
Answer:
[tex]617\frac{4}{5}[/tex]
Step-by-step explanation:
We have been given that a bird flies from its nest [tex]528\frac{1}{5}[/tex] to the bottom of the canyon [tex]-89\frac{3}{5}[/tex].
First of all, we will convert both mixed fractions into improper fraction.
[tex]528\frac{1}{5}\Rightarrow \frac{2640+1}{5}=\frac{2641}{5}[/tex]
[tex]89\frac{3}{5}\Rightarrow \frac{445+3}{5}=\frac{448}{5}[/tex]
To solve our given problem, we will find difference of both elevations as:
[tex]\frac{2641}{5}-(-\frac{448}{5})[/tex]
[tex]\frac{2641}{5}+\frac{448}{5}[/tex]
[tex]\frac{2641+448}{5}[/tex]
[tex]\frac{3089}{5}[/tex]
[tex]617\frac{4}{5}[/tex]
Therefore, the bird flown [tex]617\frac{4}{5}[/tex] units.
