Answer:
The range of g(x) is y > 0
The ranges of f(x) and h(x) are different from the range of g(x)
Step-by-step explanation:
we have
[tex]f(x)=-(\frac{6}{11})^{x}[/tex]
[tex]g(x)=(\frac{6}{11})^{-x}[/tex]
[tex]h(x)=-(\frac{6}{11})^{-x}[/tex]
Using a graphing tool
see the attached figure
Verify each statement
case A) The range of h(x) is y > 0.
The statement is false
The range of h(x) < 0
case B) The range of g(x) is y > 0. (Note the statement is The range of g(x) is y > 0 instead of The domain of g(x) is y > 0)
The statement is true (see the attached figure)
case C) The ranges of f(x) and h(x) are different from the range of g(x)
The statement is true (see the attached figure)
Because
The ranges of f(x) and h(x) are y < 0
and
The range of g(x) is y > 0
case D) The domains of f(x) and g(x) are different from the domain of h(x)
The statement is false
The domain of the three functions is the same
