Respuesta :
Answer: The molar mass of the unknown gas is 59.8 g/mol
Explanation:
According to the ideal gas equation:-
[tex]PV=nRT[/tex]
P= Pressure of the gas = 706 mmHg = 0.93 atm (760mmHg=1atm)
V= Volume of the gas = 1.64 L
T= Temperature of the gas = 59°C=(59+273)K=332 K (0°C = 273 K)
R= Value of gas constant = 0.0821 Latm\K mol
[tex]n=\frac{PV}{RT}=\frac{0.93\times 1.64L}{0.0821 \times 332}=0.056moles[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]0.056=\frac{3.35g}{\text {Molar mass}}[/tex]
[tex]{\text {Molar mass}}=59.8g[/tex]
Thus the molar mass of the unknown gas is 59.8 g/mol
