Answer:
Vo=20.2m/s
Explanation:
We can calculate both components of initial velocity and the use them to calculate the speed as [tex]\sqrt{V_{ox}^{2}+V_{oy}^{2}}[/tex]
From the vertical movement to the maximum height:
[tex]V_{fy}=V_{oy}-g*t[/tex] since [tex]V_{fy}=0[/tex]
[tex]V_{oy}=g*t=16.19m/s[/tex]
Now, from the horizontal movement, also to the point of maximum height:
[tex]Y_{f}=Y{o}+V_{oy}*t-\frac{g*t^{2}}{2}[/tex] Solving for [tex]V_{oy}[/tex]
[tex]V_{oy}=12.1m/s[/tex]
Finally we calculate the magnitude of the new vector:
[tex]V_{o}=\sqrt{V_{ox}^{2}+V_{oy}^{2}}=20.2m/s[/tex]
