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A balloon contains a fixed amount of helium. If the initial conditions are 1.12 liters, 3.00 atmospheres, and 19 degrees Celsius, what will the final volume be when the balloon is exposed to 1.00 atmosphere pressure and 22 degrees Celsius?

Respuesta :

Answer:

The final volume will be 3.39 liters

Explanation:

P1V1/T1 = P2V2/T2

P1 = 3 atm

T1 = 19( degrees celsius) + 273 = 292 K

V2 = TO BE DETERMINED

P2 =1 atm

T2 = 22( degrees celsius) + 273 = 295 k

P1V1/T1 = P2V2/T2

V2 = P1V1T2/P2T1 = (3)(1.12)(295)/(1)292) = 3.39 Liters

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