A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is used to measure the glucose concentration in the blood sample five times. The measured glucose concentrations are 98.4 , 104.3 , 97.4 , 106.7 , and 93.0 mg/dL. Calculate the absolute error and relative error for each measurement made by the glucose monitor.

Respuesta :

Explanation:

Actual value = 102.0 mg/dL

Calculation of absolute error and relative error for the measured value, 98.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 98.4 | = 3.6

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{3.6}{102.0} = 0.03529[/tex]

Calculation of absolute error and relative error for the measured value, 104.3 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 104.3 | = 2.3

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{2.3}{102.0} = 0.02255[/tex]

Calculation of absolute error and relative error for the measured value, 97.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 97.4 | = 4.6

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{4.6}{102.0} = 0.04509[/tex]

Calculation of absolute error and relative error for the measured value, 106.7 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 106.7 | = 4.7

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{4.7}{102.0} = 0.04607[/tex]

Calculation of absolute error and relative error for the measured value, 93.0 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 93 | = 9

Relative error = [tex]\frac{Absolute\ error}{Actual\ value}[/tex]

                       = [tex]\frac{9}{102.0} = 0.08823[/tex]