A cyclist moving towards right with an acceleration of 4m/s² at t = 0 he has travelled 5 m moving towards the right at 15 m/s what will be his final position

Respuesta :

Answer:

[tex]x=2t^2+15t+5[/tex]

Explanation:

[tex]x=\frac{1}{2}at^2+v_0t+x_0[/tex]